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[iOS] Better Find Next Textfield Algo #13174

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Feb 9, 2023
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44 changes: 23 additions & 21 deletions src/Core/src/Platform/iOS/ViewExtensions.cs
Original file line number Diff line number Diff line change
Expand Up @@ -735,40 +735,42 @@ internal static void UpdateLayerBorder(this CoreAnimation.CALayer layer, IButton
return null;
}

internal static UIView? FindNextView(this UIView view, UIView superView, Func<UIView, bool> isValidType)
internal static UIView? FindNextView(this UIView view, UIView containerView, Func<UIView, bool> isValidType)
{
var passedOriginal = false;
UIView? nextView = null;

var nextView = superView.FindNextView(view, ref passedOriginal, isValidType);
while (view != containerView && view is not null)
{
var siblings = view.Superview.Subviews;
nextView = view.FindNextView(siblings.IndexOf(view) + 1, isValidType);

if (nextView is not null)
break;

view = view.Superview;
}

// if we did not find the next view, try to find the first one
nextView ??= superView.FindNextView(null, ref passedOriginal, isValidType);
nextView ??= containerView.Subviews[0].FindNextView(0, isValidType);

return nextView;
}

static UIView? FindNextView(this UIView view, UIView? origView, ref bool passedOriginal, Func<UIView, bool> isValidType)
static UIView? FindNextView(this UIView view, int index, Func<UIView, bool> isValidType)
{
foreach (var child in view.Subviews)
// search through the view's siblings and traverse down their branches
var siblings = view.Superview.Subviews;
for (int i = index; i < siblings.Length; i++)
{
if (isValidType(child))
if (siblings[i].Subviews.Length > 0)
{
if (origView is null)
return child;

if (passedOriginal)
return child;

if (child == origView)
passedOriginal = true;
var childVal = siblings[i].Subviews[0].FindNextView(0, isValidType);
if (childVal is not null)
return childVal;
}

else if (child.Subviews.Length > 0 && !child.Hidden && child.Alpha > 0f)
{
var nextLevel = child.FindNextView(origView, ref passedOriginal, isValidType);
if (nextLevel is not null)
return nextLevel;
}
if (isValidType(siblings[i]))
return siblings[i];
}

return null;
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