How to disable first key in combination conditionally

[jodhsinghnahal]

When I type jk this will also type j then esc.

 {
        "input_combination": [

            {
                "type": 1,
                "code": 36,
                "origin_hash": "d5d191ac440b53de83839d8e9d2bcb5f"
            },

            {
                "type": 1,
                "code": 37,
                "origin_hash": "d5d191ac440b53de83839d8e9d2bcb5f"
            }

        ],
        "target_uinput": "keyboard",
        "output_symbol": "KEY_ESC",
        "mapping_type": "key_macro"

    }

I also tried this but if I have text in firefox search bar with autocomplete it will still write the j.

{
        "input_combination": [

            {
                "type": 1,
                "code": 36
            }

        ],
        "target_uinput": "keyboard",
        "output_symbol": "set(foo, 1).hold_keys(j).set(foo, 0)",
        "mapping_type": "key_macro",
        "macro_key_sleep_ms": 1
    },

    {
        "input_combination": [

            {
                "type": 1,
                "code": 37
            }

        ],

        "target_uinput": "keyboard",
        "output_symbol": "if_eq($foo, 1, key(KEY_ESC).key(KEY_BACKSPACE), hold_keys(k))",
        "mapping_type": "key_macro",
        "macro_key_sleep_ms": 1
    }

[sezanzeb]

So you want to have a functioning "j" key, but if combined with "k" inject "esc" but not the "j"?

Turns out there is a solution, but it seems to exploit a race condition or something:

map j to:

set(j, 1)	
.if_single(
    hold_keys(j),
    wait(1).if_eq($j, 1, key(j)),
    200
)
.set(j, 0)

map k to:

if_eq(
    $j,
    1,
    set(j, 0).hold_keys(Escape),
    hold_keys(k)
)

By doing wait(1) it gives the second macro time to set j to 0. And as it turns out, wait(1) is still faster than other unrelated keys for some reason. So other keys that you press appear after j. Even wait(10) seems to be fine. Couldn't figure out what causes that lag, but it makes this possible.