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Professor and Parties - GFG/README.md

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+# Professor and Parties
+## Easy
+<div class="problem-statement">
+                <p></p><p><span style="font-size:18px">A professor went to a party. Being an erudite person, he classified the party into two categories. He proposed that if all the persons in the party are wearing different colored robes, then that is a girl’s only party. If we even get one duplicate color, it must be a boy’s party. The colors of the robes are represented by positive integers.</span></p>
+
+<p>&nbsp;</p>
+
+<p><span style="font-size:18px"><strong>Example</strong> <strong>1:</strong></span></p>
+
+<pre><span style="font-size:18px"><strong>Input</strong>
+N = 5
+A[] = {1, 2, 3, 4, 7}
+<strong>Output</strong>
+GIRLS
+<strong>Explanation:</strong>
+All the colors are unique so it's a GIRLS party.</span></pre>
+
+<p>&nbsp;</p>
+
+<p><span style="font-size:18px"><strong>Example</strong> <strong>2:</strong></span></p>
+
+<pre><span style="font-size:18px"><strong>Input</strong>
+N = 6
+A[] = {1, 3, 2, 4, 5, 1}
+<strong>Output</strong>
+BOYS
+<strong>Explanation:</strong>
+There are two colors 1. So it's a BOYS party.
+</span></pre>
+
+<p>&nbsp;</p>
+
+<p><br>
+<span style="font-size:18px"><strong>Your task:</strong><br>
+You <strong>don't</strong> need to print the answer, printing is done by the driver code itself. You have to complete the function <strong>PartyType()</strong> which takes the array <strong>A[]</strong> and its size <strong>N</strong><strong> </strong>as inputs and returns&nbsp; “<strong>BOYS</strong>” (without quotes) if it’s a boy’s party, else returns “<strong>GIRLS</strong>”.</span></p>
+
+<p>&nbsp;</p>
+
+<p><span style="font-size:18px"><strong>Expected Time Complexity: </strong>O(N)<br>
+<strong>Expected Auxiliary Space: </strong>O(N)</span></p>
+
+<p>&nbsp;</p>
+
+<p><span style="font-size:18px"><strong>Constraints</strong><br>
+1 ≤ N ≤ 10<sup>5</sup><br>
+1 ≤ A<sub>i </sub>≤ 10<sup>9</sup></span></p>
+ <p></p>
+            </div>