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Copy path605. Can Place Flowers.java
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605. Can Place Flowers.java
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E
tags: Array, Greedy
time: O(n)
space: O(1)
#### Array
- just check flowerbed[i-1] & flowerbed[i+1] and count
```
/*
Suppose you have a long flowerbed in which some of the plots are planted and some are not. However, flowers cannot be planted in adjacent plots - they would compete for water and both would die.
Given a flowerbed (represented as an array containing 0 and 1, where 0 means empty and 1 means not empty), and a number n, return if n new flowers can be planted in it without violating the no-adjacent-flowers rule.
Example 1:
Input: flowerbed = [1,0,0,0,1], n = 1
Output: True
Example 2:
Input: flowerbed = [1,0,0,0,1], n = 2
Output: False
Note:
The input array won't violate no-adjacent-flowers rule.
The input array size is in the range of [1, 20000].
n is a non-negative integer which won't exceed the input array size.
*/
/*
Greedy,just check flowerbed[i-1] and move on
*/
class Solution {
public boolean canPlaceFlowers(int[] flowerbed, int n) {
if (flowerbed.length == 0 || n <= 0) return true;
int m = flowerbed.length;
for (int i = 0; i < m; i++) {
if (flowerbed[i] == 1) continue;
int lastVal = i == 0 ? 0 : flowerbed[i-1];
int nextval = i == m-1? 0: flowerbed[i+1];
if (lastVal == 0 && nextval == 0) {
flowerbed[i] = 1;
n--;
}
if (n <= 0) return true;
}
return false;
}
}
```