fix: try to infer possible provider from the model name, resolves ScrapeGraphAI#805

Author: Levyathanus

scrapegraphai/graphs/abstract_graph.py

@@ -144,9 +144,18 @@ def _create_llm(self, llm_config: dict) -> object:
                         "ollama", "oneapi", "nvidia", "groq", "anthropic", "bedrock", "mistralai",
                         "hugging_face", "deepseek", "ernie", "fireworks", "togetherai"}
 
-        split_model_provider = llm_params["model"].split("/", 1)
-        llm_params["model_provider"] = split_model_provider[0]
-        llm_params["model"] = split_model_provider[1]
+        if '/' in llm_params["model"]:
+                    split_model_provider = llm_params["model"].split("/", 1)
+                    llm_params["model_provider"] = split_model_provider[0]
+                    llm_params["model"] = split_model_provider[1]
+        else:
+            possible_providers = [provider for provider, models_d in models_tokens.items() if llm_params["model"] in models_d]
+            if len(possible_providers) <= 0:
+                raise ValueError(f"""Provider {llm_params['model_provider']} is not supported. 
+                                If possible, try to use a model instance instead.""")
+            llm_params["model_provider"] = possible_providers[0]
+            print((f"Found providers {possible_providers} for model {llm_params['model']}, using {llm_params['model_provider']}.\n"
+                    "If it was not intended please specify the model provider in the graph configuration"))
 
         if llm_params["model_provider"] not in known_providers:
             raise ValueError(f"""Provider {llm_params['model_provider']} is not supported.