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Copy path349.两个数组的交集.js
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349.两个数组的交集.js
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/*
* @lc app=leetcode.cn id=349 lang=javascript
*
* [349] 两个数组的交集
*
* https://leetcode-cn.com/problems/intersection-of-two-arrays/description/
*
* algorithms
* Easy (65.08%)
* Likes: 120
* Dislikes: 0
* Total Accepted: 28.7K
* Total Submissions: 44.2K
* Testcase Example: '[1,2,2,1]\n[2,2]'
*
* 给定两个数组,编写一个函数来计算它们的交集。
*
* 示例 1:
*
* 输入: nums1 = [1,2,2,1], nums2 = [2,2]
* 输出: [2]
*
*
* 示例 2:
*
* 输入: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
* 输出: [9,4]
*
* 说明:
*
*
* 输出结果中的每个元素一定是唯一的。
* 我们可以不考虑输出结果的顺序。
*
*
*/
/**
* @param {number[]} nums1
* @param {number[]} nums2
* @return {number[]}
*/
var intersection = function(nums1, nums2) {
let lp = 0,
rp = 0;
const dict = {};
while (lp < nums1.length) {
const lpv = nums1[lp];
while (rp < nums2.length) {
if (lpv === nums2[rp++]) {
dict[lpv] = 1;
}
}
rp = 0;
lp++;
}
return Object.keys(dict).map(Number);
};