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2.两数相加.js
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/*
* @lc app=leetcode.cn id=2 lang=javascript
*
* [2] 两数相加
*
* https://leetcode-cn.com/problems/add-two-numbers/description/
*
* algorithms
* Medium (35.24%)
* Likes: 2858
* Dislikes: 0
* Total Accepted: 183.9K
* Total Submissions: 521.3K
* Testcase Example: '[2,4,3]\n[5,6,4]'
*
* 给出两个 非空 的链表用来表示两个非负的整数。其中,它们各自的位数是按照 逆序 的方式存储的,并且它们的每个节点只能存储 一位 数字。
*
* 如果,我们将这两个数相加起来,则会返回一个新的链表来表示它们的和。
*
* 您可以假设除了数字 0 之外,这两个数都不会以 0 开头。
*
* 示例:
*
* 输入:(2 -> 4 -> 3) + (5 -> 6 -> 4)
* 输出:7 -> 0 -> 8
* 原因:342 + 465 = 807
*
*
*/
/* *
* Definition for singly-linked list.
* function ListNode(val) {
* this.val = val;
* this.next = null;
* }
*/
/**
* @param {ListNode} l1
* @param {ListNode} l2
* @return {ListNode}
*/
var addTwoNumbers = function(l1, l2) {
const l3 = new ListNode(null);
let carry = 0,
sum = 0,
head = l3,
l1Head = l1,
l2Head = l2;
while (l1Head || l2Head) {
let tmp = 0;
if (l1Head && l2Head) {
tmp = l1Head.val + l2Head.val;
} else {
tmp = l1Head ? l1Head.val : l2Head.val;
}
sum = (tmp + carry) % 10;
carry = Math.floor((tmp + carry) / 10);
head.next = new ListNode(sum);
head = head.next;
l1Head && (l1Head = l1Head.next);
l2Head && (l2Head = l2Head.next);
}
carry && (head.next = new ListNode(carry));
return l3.next;
};