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Copy path145.二叉树的后序遍历.js
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145.二叉树的后序遍历.js
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/*
* @lc app=leetcode.cn id=145 lang=javascript
*
* [145] 二叉树的后序遍历
*
* https://leetcode-cn.com/problems/binary-tree-postorder-traversal/description/
*
* algorithms
* Hard (67.46%)
* Likes: 172
* Dislikes: 0
* Total Accepted: 33.1K
* Total Submissions: 48.6K
* Testcase Example: '[1,null,2,3]'
*
* 给定一个二叉树,返回它的 后序 遍历。
*
* 示例:
*
* 输入: [1,null,2,3]
* 1
* \
* 2
* /
* 3
*
* 输出: [3,2,1]
*
* 进阶: 递归算法很简单,你可以通过迭代算法完成吗?
*
*/
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
// 后序遍历: 先遍历左子节点, 再遍历右子节点, 最后访问根节点
// @lc code=start
/**
* 递归
* @param {TreeNode} root
* @return {number[]}
*/
var postorderTraversal = function(root) {
if (!root) return [];
var res = [];
/**
* @param {TreeNode} node
* @param {number[]} nums
*/
function backtrack(node, nums) {
node.left && backtrack(node.left, nums);
node.right && backtrack(node.right, nums);
nums.push(node.val);
}
backtrack(root, res);
return res;
};
// @lc code=end